16x^2y^5+8x^4y^3=4xy^3(4xy^2+2x^3)

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Solution for 16x^2y^5+8x^4y^3=4xy^3(4xy^2+2x^3) equation: 


Simplifying
16x2y5 + 8x4y3 = 4xy3(4xy2 + 2x3)
16x2y5 + 8x4y3 = (4xy2 * 4xy3 + 2x3 * 4xy3)
16x2y5 + 8x4y3 = (16x2y5 + 8x4y3)

Add '-16x2y5' to each side of the equation.
16x2y5 + -16x2y5 + 8x4y3 = 16x2y5 + -16x2y5 + 8x4y3

Combine like terms: 16x2y5 + -16x2y5 = 0
0 + 8x4y3 = 16x2y5 + -16x2y5 + 8x4y3
8x4y3 = 16x2y5 + -16x2y5 + 8x4y3

Combine like terms: 16x2y5 + -16x2y5 = 0
8x4y3 = 0 + 8x4y3
8x4y3 = 8x4y3

Add '-8x4y3' to each side of the equation.
8x4y3 + -8x4y3 = 8x4y3 + -8x4y3

Combine like terms: 8x4y3 + -8x4y3 = 0
0 = 8x4y3 + -8x4y3

Combine like terms: 8x4y3 + -8x4y3 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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